Skip to content

Is P0 the initial state covariance matrix or the square root of the initial state covariance matrix? #325

Open
@rklees

Description

I wonder if someone could clarify what P0 really is. For instance, in the example notebooks to pymc-experimental , I found the following statement:

P0_diag = pm.Gamma("P0_diag", alpha=2, beta=5, dims=P0_dims[0])
P0 = pm.Deterministic("P0", pt.diag(P0_diag), dims=P0_dims)

A Gamma distribution is usually used as a prior for a standard deviation, not for a variance. So, does P0 as used above is a covariance matrix or the square-root of a covariance matrix?

Moreover, in structural.py, I frequently find statements like the following for a cycle:

if self.innovations:
sigma_cycle = self.make_and_register_variable(f"sigma_{self.name}", shape=(1,))
self.ssm["state_cov", :, :] = pt.eye(self.k_posdef) * sigma_cycle

So the name "state_cov" suggests that I define a variance, however, the right-hand side suggests that I define a standard deviation (sigma_cycle is the standard deviation of the cycle disturbance).

Any help would be appreciated.

Metadata

Assignees

No one assigned

    Labels

    No labels
    No labels

    Type

    No type

    Projects

    No projects

    Milestone

    No milestone

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions