- print elements in the column 3 that has the word "good" in the other columns
$ awk '/good/ { print $3 }' inventory
- syntax:
$ awk -f {PROGRAM FILE} FILENAME
- awk program is:
PATTERN{
ACTION 1
ACTION 2
ACTION 3
}
with
. (Dot) Match any character
* Match zero or more character
^ Match beginning of line
$ Match end of line
\ Escape character following
[ ] List
{ } Match range of instance
+ Match one more preceding
? Match zero or one preceding
| Separate choices to match
if (condition)
{
Statement 1
Statement 2
Statement N
if condition is TRUE
}
else
{
Statement 1
Statement 2
Statement N
if condition is FALSE
}