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datetime="2019-02-28T16:23:26+08:00">2019-02-28 </time> |   Visit count </div></header><div class="post-body" itemprop="articleBody">CountDownLatch允许一个或多个线程等待其他线程完成操作。定义CountDownLatch的时候，需要传入一个正数来初始化计数器（虽然传入0也可以，但这样的话CountDownLatch没什么实际意义）。其<code>countDown</code>方法用于递减计数器，<code>await</code>方法会使当前线程阻塞，直到计数器递减为0。所以CountDownLatch常用于多个线程之间的协调工作。<a id="more"></a><h2 id="CountDownLatch示例"><a href="#CountDownLatch示例" class="headerlink" title="CountDownLatch示例"></a>CountDownLatch示例</h2>假设我们现在有这样一个需求：<ol><li>从数据库获取数据</li><li>对这批数据进行处理</li><li>保存这批数据</li></ol>为了让程序执行效率更高，第2步中我们可以使用多线程来并行处理这批数据，大致过程如下所示：<figure class="highlight java"><table><tr><td class="gutter"><pre>1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 </pre></td><td class="code"><pre>public class CountDownLatchTest { public static void main(String[] args) throws InterruptedException { // 1. 模拟从数据库获取数据 int[] data = query(); System.out.println("获取数据完毕"); // 2. 数据处理 IntStream.range(0, data.length).forEach(i -> { ExecutorService.execute(() -> { System.out.println(Thread.currentThread() + "处理第" + (i + 1) + "条数据"); int value = data[i]; if (value % 2 == 0) { data[i] = value * 2; } else { data[i] = value * 10; } }); }); System.out.println("所有数据都处理完了"); // 关闭线程池 ExecutorService.shutdown(); // 3. 保存数据 save(data); } private static int[] query() { return new int[]{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; } private static void save(int[] data) { System.out.println("保存数据 - " + Arrays.toString(data)); } } </pre></td></tr></table></figure>由于线程获取CPU时间片的不确定性，所以有可能数据还没有处理完毕，第3步就执行完了：<figure class="highlight plain"><table><tr><td class="gutter"><pre>1 2 3 4 5 6 7 8 9 10 11 12 13 </pre></td><td class="code"><pre>获取数据完毕 所有数据都处理完了 保存数据 - [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] Thread[pool-1-thread-2,5,main]处理第2条数据 Thread[pool-1-thread-1,5,main]处理第1条数据 Thread[pool-1-thread-2,5,main]处理第3条数据 Thread[pool-1-thread-1,5,main]处理第4条数据 Thread[pool-1-thread-1,5,main]处理第6条数据 Thread[pool-1-thread-2,5,main]处理第5条数据 Thread[pool-1-thread-1,5,main]处理第7条数据 Thread[pool-1-thread-1,5,main]处理第9条数据 Thread[pool-1-thread-2,5,main]处理第8条数据 Thread[pool-1-thread-1,5,main]处理第10条数据 </pre></td></tr></table></figure>我们可以借助CountDownLatch解决这个问题：<figure class="highlight java"><table><tr><td class="gutter"><pre>1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 </pre></td><td class="code"><pre>public class CountDownLatchTest { private static ExecutorService ExecutorService = Executors.newFixedThreadPool(2); private static CountDownLatch latch = new CountDownLatch(10); public static void main(String[] args) throws InterruptedException { // 1. 模拟从数据库获取数据 int[] data = query(); System.out.println("获取数据完毕"); // 2. 数据处理 IntStream.range(0, data.length).forEach(i -> { ExecutorService.execute(() -> { System.out.println(Thread.currentThread() + "处理第" + (i + 1) + "条数据"); int value = data[i]; if (value % 2 == 0) { data[i] = value * 2; } else { data[i] = value * 10; } latch.countDown(); }); }); latch.await(); System.out.println("所有数据都处理完了"); // 关闭线程池 ExecutorService.shutdown(); // 3. 保存数据 save(data); } private static int[] query() { return new int[]{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; } private static void save(int[] data) { System.out.println("保存数据 - " + Arrays.toString(data)); } } </pre></td></tr></table></figure>我们定义了一个CountDownLatch，计数器值为10，和数据量一致。然后在第2步中，当每个线程执行完毕的时候调用<code>countDown</code>方法，让计数器减1。在第3步前调用<code>await</code>方法让main线程阻塞等待，直到计数器被减为0。所以这就保证了只有当所有数据加工完毕才执行保存数据操作。执行方法，程序输出如下所示：<figure class="highlight plain"><table><tr><td class="gutter"><pre>1 2 3 4 5 6 7 8 9 10 11 12 13 </pre></td><td class="code"><pre>获取数据完毕 Thread[pool-1-thread-1,5,main]处理第1条数据 Thread[pool-1-thread-1,5,main]处理第3条数据 Thread[pool-1-thread-1,5,main]处理第4条数据 Thread[pool-1-thread-1,5,main]处理第5条数据 Thread[pool-1-thread-1,5,main]处理第6条数据 Thread[pool-1-thread-1,5,main]处理第7条数据 Thread[pool-1-thread-1,5,main]处理第8条数据 Thread[pool-1-thread-1,5,main]处理第9条数据 Thread[pool-1-thread-1,5,main]处理第10条数据 Thread[pool-1-thread-2,5,main]处理第2条数据 所有数据都处理完了 保存数据 - [10, 4, 30, 8, 50, 12, 70, 16, 90, 20] </pre></td></tr></table></figure><code>await</code>有重载方法：<code>await(long timeout, TimeUnit unit)</code>，设置最大等待时间，超过这个时间程序将继续执行不再被阻塞：<figure class="highlight java"><table><tr><td class="gutter"><pre>1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 </pre></td><td class="code"><pre>public class CountDownLatchTest { public static void main(String[] args) throws InterruptedException { final CountDownLatch latch = new CountDownLatch(1); new Thread(() -> { try { TimeUnit.SECONDS.sleep(4); System.out.println(Thread.currentThread() + "线程执行完毕"); } catch (InterruptedException e) { e.printStackTrace(); } finally { latch.countDown(); } }, "thread1").start(); latch.await(3, TimeUnit.SECONDS); // 最多等待 3秒 System.out.println("main线程执行完毕"); } } </pre></td></tr></table></figure>输出如下：<figure class="highlight plain"><table><tr><td class="gutter"><pre>1 2 </pre></td><td 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