Handle failure of subprocess more gracefully

Fixes UnboundLocalError: local variable 'output' referenced before assignment
paulgear · Jan 5, 2024 · 55e7f21 · 55e7f21
1 parent 373a0b0
commit 55e7f21
Showing 1 changed file with 1 addition and 0 deletions.
diff --git a/src/process.py b/src/process.py
@@ -35,6 +35,7 @@
 
 
 def execute_subprocess(cmd, timeout, debug, errfatal):
+    output = None
     try:
         output = subprocess.check_output(
             cmd,