Changed description of output parameter

jcv16 · Mar 17, 2017 · 88a1ea2 · 88a1ea2
1 parent 91c84e0
commit 88a1ea2
Showing 1 changed file with 1 addition and 1 deletion.
diff --git a/docs/csharp/tour-of-csharp/classes-and-objects.md b/docs/csharp/tour-of-csharp/classes-and-objects.md
@@ -130,7 +130,7 @@ A *reference parameter* is used for both input and output parameter passing. The
 
 [!code-csharp[swapExample](../../../samples/snippets/csharp/tour/classes-and-objects/RefExample.cs#L3-L18)]
 
-An *output parameter* is used for output parameter passing. An output parameter is similar to a reference parameter except that the initial value of the caller-provided argument is unimportant. An output parameter is declared with the `out` modifier. The following example shows the use of `out` parameters.
+An *output parameter* is used for passing arguments by reference. It is similar to a reference parameter, except that it does not require that you explicitly assign a value to the caller-provided argument. An output parameter is declared with the `out` modifier. The following example shows the use of `out` parameters using the syntax introduced in C# 7.
 
 [!code-csharp[OutExample](../../../samples/snippets/csharp/tour/classes-and-objects/OutExample.cs#L3-L17)]