Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

check whether integer is even or odd using bit manupulation #7099

Merged
merged 8 commits into from
Oct 23, 2022
Merged
Changes from 1 commit
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
40 changes: 40 additions & 0 deletions bit_manipulation/even_or_not.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,40 @@
def is_even(number: int) -> bool:
"""
return true if the input integer is even
Explanation: Lets take a look at the following deicmal to binary conversions
2 => 10
14 => 1110
100 => 1100100
3 => 11
13 => 1101
101 => 1100101
from the above examples we can observe that
for all the odd integers there is always 1 set bit at the end
also, 1 in binary can be represented as 001, 00001, or 0000001
so for any odd integer n => n&1 is always equlas 1 else the integer is even

>>> is_even(1)
False
>>> is_even(4)
True
>>> is_even(9)
False
>>> is_even(15)
False
>>> is_even(40)
True
>>> is_even(100)
True
>>> is_even(101)
False
"""
if number & 1 == 0:
return True
else:
return False
cclauss marked this conversation as resolved.
Show resolved Hide resolved


if __name__ == "__main__":
import doctest

doctest.testmod()