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// 단순하게 정렬해서 일치하지 않으면 출력하고 리스트를 벗어나면 그대로 checkNum을 출력하는 방식 | ||
// 시간복잡도 : O(NlogN) | ||
// 공간복잡도 : O(1) | ||
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class SolutionGotprgmer { | ||
public int missingNumber(int[] nums) { | ||
Arrays.sort(nums); | ||
int checkNum = 0; | ||
for(int i=0;i<nums.length;i++){ | ||
if(nums[i] != checkNum){ | ||
return checkNum; | ||
} | ||
checkNum += 1; | ||
} | ||
return checkNum; | ||
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} | ||
} |